-30x^2+25x+5=0

Solution for -30x^2+25x+5=0 equation:

-30x^2+25x+5=0

a = -30; b = 25; c = +5;
Δ = b2-4ac
Δ = 252-4·(-30)·5
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-35}{2*-30}=\frac{-60}{-60}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+35}{2*-30}=\frac{10}{-60}
=-1/6
$